Problem Description :
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
খুবই বাংলা প্রবলেম ক্লাস 8/9 এর পোলাপানেরাও পারবে। n(n+1)/2 এই ফর্মুলা ব্যাবহার করা হইসে বাকিটা সহজ যে কেউ পড়লেই বুঝবে ।
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| #include<stdio.h> | |
| #include<math.h> | |
| int main() | |
| { | |
| int n=100,i,j=0,k,sum; | |
| k=n*(n+1); | |
| sum=pow(k/2,2); | |
| printf("%d ",sum); | |
| for(i=1;i<=100;i++){ | |
| j=j+pow(i,2); | |
| } | |
| printf("\n%d \n",j); | |
| printf("Difference : %d \n",sum-j); | |
| return 0; | |
| } |
