Problem Name : Primary Arithmetic
Solution :
Assume that a=99 and b=9999 so how to count carry variable ?
let's see,
n1=a%10 got 9
n2=b%10 got 9
sum=9+9=18 so carry=1
n1=a%10 got 9
n2=b%10 got 9
sum=9+9=18 so carry= 1+1 (previous counted 1) and so on...
Another way if , sum is not equal or greater than 10 than carry=0.
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| // Author : Shohan | |
| // URI oj : 1212 | |
| #include<stdio.h> | |
| int long carry_num (int long a,int long b); | |
| int main() | |
| { | |
| int long a,b,sum=0,op=0,d1,d2,carry; | |
| while(scanf("%ld %ld",&a,&b)==2){ | |
| if(a==0 && b==0) | |
| break; | |
| op=carry_num(a,b); | |
| if(op==0) | |
| printf ("No carry operation.\n"); | |
| else if(op==1) | |
| printf ("1 carry operation.\n"); | |
| else | |
| printf("%ld carry operations.\n",op); | |
| } | |
| return 0; | |
| } | |
| int long carry_num(int long a,int long b) | |
| { | |
| int long op,carry,d1,d2,sum; | |
| op=0; | |
| carry=0; | |
| while(1){ | |
| d1=a%10; | |
| d2=b%10; | |
| sum=d1+d2+carry; | |
| if(sum>=10){ | |
| op++; | |
| carry=1; | |
| } | |
| else { | |
| carry=0; | |
| } | |
| a=a/10; | |
| b=b/10; | |
| if(a==0 && b==0) | |
| break; | |
| } | |
| return op; | |
| } | |
