Project Euler -- 48 (Self powers)

Problem : The series, 1¹ + 2² + 3³ + ... + 10¹⁰ = 10405071317.

Find the last ten digits of the series, 1¹ + 2² + 3³ + ... + 1000¹⁰⁰⁰.

My solution approach is,

first made a smaller version of the problem then I tried to solve it after solving this I was going to solve the bigger version.

// a. find out p=2^15

// b. print the last digit of p

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UVA -- 10127 (Ones)

Solution :

Another Approach : 

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Big Mod Algorithm

Implement Program 01 :



Implement Program 02 :





Download-Pdf  From shafaetsplanet.com for more details about BigMod or You can watch the recursion tree it might be helpful.

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